findall.py 262 B

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  1. import re
  2. pattern = re.compile('(\\d{4})-([1-9]|1[0-2])-([1-9]|[1-2][0-9]|3[01])\\b')
  3. s = 'date: 2020-1-1, 2022-12-22, 2018-3-31. Wrong format: 2031-13-31, 2032-12-33 ...'
  4. result1 = pattern.findall(s)
  5. print(result1)
  6. result2 = pattern.sub('\\1',s)
  7. print(result2)