فهرست منبع

modify kernel samples,add licence

yangjie 7 سال پیش
والد
کامیت
619db387e6
7فایلهای تغییر یافته به همراه262 افزوده شده و 12 حذف شده
  1. 52 0
      .gitignore
  2. 202 0
      LICENSE
  3. 2 0
      idlehook/idlehook_sample.c
  4. 1 1
      mempool/memp_sample.c
  5. 2 10
      mutex/mutex_sample.c
  6. 2 0
      semaphore/producer_consumer.c
  7. 1 1
      semaphore/semaphore_sample.c

+ 52 - 0
.gitignore

@@ -0,0 +1,52 @@
+# Prerequisites
+*.d
+
+# Object files
+*.o
+*.ko
+*.obj
+*.elf
+
+# Linker output
+*.ilk
+*.map
+*.exp
+
+# Precompiled Headers
+*.gch
+*.pch
+
+# Libraries
+*.lib
+*.a
+*.la
+*.lo
+
+# Shared objects (inc. Windows DLLs)
+*.dll
+*.so
+*.so.*
+*.dylib
+
+# Executables
+*.exe
+*.out
+*.app
+*.i*86
+*.x86_64
+*.hex
+
+# Debug files
+*.dSYM/
+*.su
+*.idb
+*.pdb
+
+# Kernel Module Compile Results
+*.mod*
+*.cmd
+.tmp_versions/
+modules.order
+Module.symvers
+Mkfile.old
+dkms.conf

+ 202 - 0
LICENSE

@@ -0,0 +1,202 @@
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+

+ 2 - 0
idlehook/idlehook_sample.c

@@ -56,6 +56,8 @@ static void thread_entry(void *parameter)
         rt_thread_mdelay(500);
     }
     rt_kprintf("delete idle hook.\n");
+	
+	/* 删除空闲钩子函数 */
     rt_thread_idle_delhook(idle_hook);
     rt_kprintf("thread1 finish.\n");
 }

+ 1 - 1
mempool/memp_sample.c

@@ -16,7 +16,7 @@
  * 内存块
  */
 #include <rtthread.h>
-#include <rtdef.h>
+
 static rt_uint8_t *ptr[50];
 static rt_uint8_t mempool[4096];
 static struct rt_mempool mp;

+ 2 - 10
mutex/mutex_sample.c

@@ -16,7 +16,6 @@
  * 线程2也会对2个number分别进行加1操作。使用互斥量保证2个number值保持一致
  */
 #include <rtthread.h>
-#define SAMPLE_USE_MUTEX  //打开该则使用互斥量保护线程1对number的操作
 
 #define THREAD_PRIORITY         8
 #define THREAD_TIMESLICE        5
@@ -32,22 +31,15 @@ static void rt_thread_entry1(void *parameter)
 {
       while(1)
       {
-          #ifdef SAMPLE_USE_MUTEX
           /* 线程1获取到互斥量后,先后对number1、number2进行加1操作,然后释放互斥量 */
-          rt_mutex_take(dynamic_mutex, RT_WAITING_FOREVER);
-          #endif
-          
+          rt_mutex_take(dynamic_mutex, RT_WAITING_FOREVER);          
           number1++;
           rt_thread_mdelay(10);
-          number2++;
-          
-          #ifdef SAMPLE_USE_MUTEX
+          number2++;          
           rt_mutex_release(dynamic_mutex);
-          #endif
        }	    
 }
 
-
 ALIGN(RT_ALIGN_SIZE)
 static char thread2_stack[1024];
 static struct rt_thread thread2;

+ 2 - 0
semaphore/producer_consumer.c

@@ -12,6 +12,8 @@
  * 程序清单:生产者消费者例子
  *
  * 这个例子中将创建两个线程用于实现生产者消费者问题
+ *(1)生产者线程将cnt值每次加1并循环存入array数组的5个成员内;
+ *(2)消费者线程将生产者中生产的数值打印出来,并累加求和
  */
 #include <rtthread.h>
 

+ 1 - 1
semaphore/semaphore_sample.c

@@ -39,7 +39,7 @@ static void rt_thread1_entry(void *parameter)
             return; 
         
         /* count每计数10次,就释放一次信号量 */
-         if(0 == (count%10))
+         if(0 == (count % 10))
         {
             rt_kprintf("t1 release a dynamic semaphore.\n" ); 
             rt_sem_release(dynamic_sem);